How do you solve #x^2+22x+121=0#?
1 Answer
Jun 23, 2018
Explanation:
#"this is a "color(blue)"perfect square"#
#•color(white)(x)(a+-b)^2=a^2+-2ab+b^2#
#"with "a=x" and "b=11#
#2ab=2xx x xx11=22x#
#(x+11)^2=0#
#(x+11)(x+11)=0#
#rArrx=-11" of multiplicity 2"#