How do you solve $x^2 - 17x + 72 =0$ using the quadratic formula?

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Answer 1 · 2016-02-26T09:09:20

Solution is $x=9$ or $x=8$

For equation $ax^2+bx+c=0$ , the solution given by quadratic formula is $(-b+-sqrt(b^2-4ac))/(2a)$ .

To solve $x^2−17x+72=0$ , we know that $a=1$ , $b=-17$ and $c=72$

Hence, solution is given by $(-(-17)+-sqrt((-17)^2-4*1*72))/(2*1)$ or

$(17+-sqrt(289-288))/2$ or $(17+-1)/2$ or $(17+1)/2$ and $(17-1)/2$

Hence, solution is $x=9$ or $x=8$

How do you solve x^2 - 17x + 72 =0x^2 - 17x + 72 =0 using the quadratic formula?