Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you solve $x^2-16=0$ ?

1 Answer

Konstantinos Michailidis

Jul 25, 2016

By using the identity $a^2-b^2=(a-b)*(a+b)$ we have that

$x^2-16=0=>x^2-4^2=0=>(x-4)(x+4)=0$

Hence the solutions are $x_1=-4,x_2=4$

Related questions

See all questions in Use Square Roots to Solve Quadratic Equations

Impact of this question

12249 views around the world

You can reuse this answer
Creative Commons License