How do you solve $(x-1)^2=49$ ?

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Answer 1 · 2015-07-11T03:38:09

I found:
$x_1=8$
$x_2=-6$

Take the square root of both sides and get:
$x-1=+-sqrt(49)=+-7$
rearranging to isolate $x$ you get two solutions:
$x_1=1+7=8$
$x_2=1-7=-6$

How do you solve (x-1)^2=49(x-1)^2=49?