How do you solve using this equation ( $2x^2 = 40$ ) using the square root property?

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Answer 1 · 2015-08-17T15:42:25

We first divide both sides by $2$ to get $x^2=20$

Then we take the square root at both sides, but remember that both

$sqrt20and -sqrt20$ give $20$ when squared.

So $x_(1,2)=+-sqrt20=+-2sqrt5$ (two answers)

How do you solve using this equation (2x^2 = 402x^2 = 40) using the square root property?