How do you solve using the quadratic formula $x^2-7x-8=0$ ?

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Answer 1 · 2016-11-13T22:35:12

$x = 8$ and $x = -1$

This quadratic can be factored to:

$(x - 8)(x + 1) = 0$

Solving for $(x - 8)$ gives:

$((x - 8)(x + 1))/((x + 1)) = 0/(x + 1)$

$x - 8 = 0$

$x - 8 + 8 = 0 + 8$

$x = 8$

Solving for $(x + 1)$ gives:

$((x - 8)(x + 1))/((x - 8)) = 0/(x - 8)$

$x + 1 = 0$

$x + 1 - 1 = 0 - 1$

$x = -1$

How do you solve using the quadratic formula x^2-7x-8=0x^2-7x-8=0?