How do you solve using the quadratic formula $6x^2 + 12x=-3$ ?

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Answer 1 · 2015-05-12T15:37:46

A quadratic equation is written in the form:
$ax^2 + bx + c = 0$

The given equation $6x^2 + 12x = -3$ can be rewritten as $6x^2+12x+3=0$

Where:
$a=6$
$b=12$
$c=3$

The quadratic formula can be used to find the roots of any quadratic equation.

$x= (-b+- sqrt(b^2-4ac))/(2a)$

So I encourage you to plug in the values from this equation and simplify.

The answers should be $x = −1.70711 and x= −0.292893$

How do you solve using the quadratic formula 6x^2 + 12x=-36x^2 + 12x=-3?