How do you solve using the quadratic formula $5x^2 – x + 12 = 0$ ?

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Answer 1 · 2018-05-14T14:07:16

See a solution process below;

For $color(red)(a)x^2 + color(blue)(b)x + color(green)(c) = 0$ , the values of $x$ which are the solutions to the equation are given by:

$x = (-color(blue)(b) +- sqrt(color(blue)(b)^2 - (4color(red)(a)color(green)(c))))/(2 * color(red)(a))$

Substituting:

$color(red)(5)$ for $color(red)(a)$

$color(blue)(-1)$ for $color(blue)(b)$

$color(green)(12)$ for $color(green)(c)$ gives:

$x = (-(color(blue)(-1)) +- sqrt(color(blue)(-1)^2 - (4 * color(red)(5) * color(green)(12))))/(2 * color(red)(5))$

$x = (1 +- sqrt(1 - 240))/10$

$x = (1 +- sqrt(-239))/10$

How do you solve using the quadratic formula 5x^2 – x + 12 = 05x^2 – x + 12 = 0?