How do you solve using the quadratic formula 3x^2-2x-5=0?

1 Answer
Shantelle
Aug 4, 2018

x = 5/3 and -1

Explanation:

3x^2 - 2x - 5 = 0

The quadratic formula is x = (-b +- sqrt(b^2 - 4ac))/(2a).

We know that a = 3, b = -2, and c = -5 based on the equation, so let's plug them into the formula and solve:
x = (-(-2) +- sqrt((-2)^2 - 4(3)(-5)))/(2(3))

x = (2 +- sqrt(4 + 60))/6

x = (2 +- sqrt(64))/6

x = (2 +- 8)/6

x = 10/6 and -6/6

x = 5/3 and -1

Hope this helps!

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