How do you solve using the quadratic formula $2x^2 + 5x - 3 = 0$ ?

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Answer 1 · 2015-05-14T20:57:48

$2x^2+5x-3 = 0$ is of the form $ax^2+bx+c = 0$ with $a=2$ , $b=5$ and $c=-3$ .

The quadratic formula tells us that this has solutions:

$x = (-b +- sqrt(b^2-4ac))/(2a)$

$= (-5 +- sqrt(5^2-4*2*(-3))) / (2*2)$

$= (-5 +- sqrt(25+24))/4$

$= (-5 +- sqrt(49))/4$

$= (-5 +- 7)/4$

In other words, $x = 1/2$ or $x = -3$

How do you solve using the quadratic formula 2x^2 + 5x - 3 = 02x^2 + 5x - 3 = 0?