How do you solve the triangle given $△ D E F, d = 36, e = 72, m ∠ D = 30$ $triangleDEF, d=36, e=72, mangleD=30$ ?

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How do you solve the triangle given $△ D E F, d = 36, e = 72, m ∠ D = 30$ $triangleDEF, d=36, e=72, mangleD=30$ ?

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Answer 1 · 2018-02-26T09:00:55

$f = 36 \sqrt{3}, ˆ F = 60^{\circ}, ˆ E = 90^{\circ}$ $color(blue)(f = 36sqrt3, hat F = 60^@, hat E = 90^@$

Explanation:

$d = 36, ˆ D = 30, e = 72$ $color(blue)(d = 36, hat D = 30, e = 72$

enter image source here

Applying law of sines,

$ˆ E = {sin}^{- 1} (\frac{sin D \cdot e}{d}) = {sin}^{- 1} (\frac{sin 30 \cdot 72}{36}) = 90^{\circ}$ $hatE = sin ^-1 ((sin D * e) / d) = sin ^-1 ((sin 30 * 72)/36) = 90^@$

$ˆ F = 180 - 30 - 90 = 60^{\circ}$ $hat F = 180 - 30 - 90 = 60^@$

It’s a right triangle with angles $30, 60, 90$ $30, 60, 90$

$:. f = sqrt3 * 36 = 62.3538$

enter image source here

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How do you solve the triangle given $△ D E F, d = 36, e = 72, m ∠ D = 30$ $triangleDEF, d=36, e=72, mangleD=30$ ?

1 Answer

Explanation:

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How do you solve the triangle given triangleDEF, d=36, e=72, mangleD=30△DEF,d=36,e=72,m∠D=30triangleDEF, d=36, e=72, mangleD=30?

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Explanation:

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How do you solve the triangle given $△ D E F, d = 36, e = 72, m ∠ D = 30$ $triangleDEF, d=36, e=72, mangleD=30$ ?