How do you solve the triangle given $triangleABC, a=8, mangleB=35, mangleC=55$ ?

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Answer 1 · 2018-06-25T12:21:48

See below

We know
$a=8$
$hatB=35$
$hatC=55$

Then however $hatA+hatB+hatC=180$ then $hatA=90$

ABC is a right triangle

By $sin$ theorem $a/sinA=b/sinB$ or $8/1=b/sin35$ then

$b=8·sin35=4.5886$

And again with leg c: $c/sin55=8/sin90$ and $c=8·sin55=6.5532$

Or by Pitagorean theorem $8^2=4.5886^2+c^2$

How do you solve the triangle given triangleABC, a=8, mangleB=35, mangleC=55triangleABC, a=8, mangleB=35, mangleC=55?