How do you solve the triangle given $A=100^circ, a=125, c=10$ ?

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Answer 1 · 2017-05-04T14:51:30

Use the Law of Sines (and a calculator)

$(sin(/_A))/a=(sin(/_C))/c$

$rarr sin(/_C)=c*(sin(/_A))/a = 10 * sin(100^@)/125~~0.07878462$

$rarr /_C = arcsin(0.07878462) ~~4.518709095^@$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$/_B = 180^@-(/_A+/_C) ~~ 75.48129^@$

$b=a/Sin(/_A) *sin(/_B) ~~122.8749758$

How do you solve the triangle given A=100^circ, a=125, c=10A=100^circ, a=125, c=10?