How do you solve the system #x - y = 4# and #x + y = 2 # by graphing?

1 Answer
Shwetank Mauria
Apr 28, 2016

Solution is #x=3# and #y=-1#

Explanation:

For solving the system #x-y=4# and #x+y=2# graphically, we should first draw these two lines.

#x-y=4# in slope of intercept form is #y=x-4# and hence it's intercept on #y# axis is #-4# and slope is #+1# i.e. positively sloping at #45^o#.

Similarly draw #x+y=2#, which in slope of intercept form is #y=-x+2# and hence it's intercept on #y# axis is #2# and slope is #-1# i.e. negatively sloping at #45^o#.

Please see the graph below. These two intersect at the point #(3,-1)#

Hence, solution is #x=3# and #y=-1#

graph{(x-y-4)(x+y-2)=0 [-10, 10, -5, 5]}

Related questions
See all questions in Graphs of Linear Systems
Impact of this question
1448 views around the world
You can reuse this answer
Creative Commons License