How do you solve the system #x-y = 1# and #4x+3y= 11# by graphing?

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Answer 1 · 2018-07-09T10:08:57

#x=2# & #y=1#

Given system of linear equations:

#x-y=1\ ..........(1)#

#4x+3y=11\ ............(2)#

Now, multiplying (1) by #3# & adding to (2) as follows

#4x+3y+3(x-y)=11+3\cdot 1#

#7x=14#

#x=2#

setting #x=2# in (1) we get

#y=x-1=2-1=1#