How do you solve the system x2+y2+8x+7=0 and x2+y2+4x+4y−5=0 and x2+y2=1?
1 Answer
There are no points where all three equations intersect.
Explanation:
We have the following equations:
Let's substitute in E3 into E1 and E2, making the
Now let's solve E1:
Now let's solve E2:
And now let's check our work by substituting into E3:
So there is no solution in this system that satisfies all three equations.
We can see this in the following graphs:
This is the graph of
graph{x^2+y^2+8x+7=0 [-20, 20, -10, 10]}
This is the graph of
graph{x^2+y^2+4x+4y-5=0 [-20, 20, -10, 10]}
This is the graph of
graph{x^2+y^2=1 [-20, 20, -10, 10]}
As you can see, there are no points where all three graphs intersect.
