How do I use substitution to find the solution of the system of equations $c + 3 d = 8$ $c+3d=8$ and $c = 4 d - 6$ $c=4d-6$ ?

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How do I use substitution to find the solution of the system of equations $c + 3 d = 8$ $c+3d=8$ and $c = 4 d - 6$ $c=4d-6$ ?

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Answer 1 · 2015-05-19T07:20:25

equations provided are:
$c + 3 d = 8$ $c + 3d =8$ ................. $(1)$ $(1)$
$c = 4 d - 6$ $c = 4d - 6$ .......... $(2)$ $(2)$

Substituting equation $(2)$ $(2)$ in equation $(1)$ $(1)$
$c + 3 d = (4 d - 6) + 3 d = 8$ $c + 3d = (4d - 6) + 3d = 8$
$7 d - 6 = 8$ $7d - 6 = 8$
$7 d = 14$ $7d = 14$
$d = 2$ $d= 2$

Substituting the value of $d$ $d$ to find $c$ $c$
$c = 4 d - 6 = 4 \times (2) - 6 = 8 - 6 = 2$ $c = 4d - 6 = 4xx(2) -6 = 8-6 =2$

the solution for the equations are $c = 2, d = 2$ $c =2 , d=2$

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How do I use substitution to find the solution of the system of equations $c + 3 d = 8$ $c+3d=8$ and $c = 4 d - 6$ $c=4d-6$ ?

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How do I use substitution to find the solution of the system of equations c+3d=8c+3d=8 and c=4d−6c=4d-6?

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How do I use substitution to find the solution of the system of equations $c + 3 d = 8$ $c+3d=8$ and $c = 4 d - 6$ $c=4d-6$ ?