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How do you solve the system $x^{2} + y^{2} - 8 = 0$ $x^2+y^2-8=0$ and $x^{2} + y^{2} - 3 x + y = 0$ $x^2+y^2-3x+y=0$ and $2 x^{2} + 2 y^{2} - 5 x - 10 = 0$ $2x^2+2y^2-5x-10=0$ ?

1 Answer

Nov 19, 2016

There is no point that satisfies all three equations. Please see the graphs.

Explanation:

![Desmos.com]( useruploads.socratic.org )

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