How do you solve the system x2+y2=7 and y=x7?

1 Answer
Oct 21, 2016

There is no solution.

Explanation:

We can use the fact that y=x7 to substitute this expression of y into the other equation.

x2+y2=7 x2+(x7)2=7

Expanding the resultant equation and then solving it:

x2+(x214x+49)=7

2x214x+42=0

Dividing through by 2:

x27x+21=0

Examining this, we see that the discriminant b24ac=494(21)=35. Since the discriminant is negative, this system has no solutions.

We can graph the two equations given originally:

graph{(x^2+y^2-7)(y-x+7)=0 [-19.64, 20.92, -13.17, 7.1]}

The two graphs never intersect, so this confirms our conclusion of no solution.