How do you solve the system by graphing #4x - 2y = -12# and #2x + y = -2#?

1 Answer
HCH
Jul 13, 2017

#x=-2#, #y=2#

Explanation:

To solve #x# and #y# in #2# or more functions, you are actually finding #x# and #y# values which satisfy all the functions.

In other words, you are finding the intersections of the functions since at intersections, the functions are having the same value for #x# and #y#

In this case, I have plotted the functions on the same plane.

The intersection point (in this case only #1#) has the coordinate (-2,2)

#:.# #x=-2#, #y=2#

graph{(4x-2y+12)(2x+y+2)=0 [-7.9, 7.9, -3.94, 3.96]}

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