How do you solve the system $3 x + y = 4$ $3x + y = 4$ , $- 6 x - 2 y = 12$ $-6x - 2y = 12$ ?

Question

How do you solve the system $3 x + y = 4$ $3x + y = 4$ , $- 6 x - 2 y = 12$ $-6x - 2y = 12$ ?

1 Answer

Related questions

What is a system of equations?
What does it mean to solve a system of equations by substitution?
How do I use substitution to find the solution of the system of equations $c + 3 d = 8$ $c+3d=8$ and $c = 4 d - 6$ $c=4d-6$ ?
How do you write a system of linear equations in two variables?
How does a system of linear equations have no solution?
How many solutions can a system of linear equations have?
What is the final step of completing a solve by substitution problem?
How do I use substitution to find the solution of the system of equations $4 x + 3 y = 7$ $4x+3y=7$ and $3 x + 5 y = 8$ $3x+5y=8$ ?
How do I use substitution to find the solution of the system of equations $y = 2 x + 1$ $y=2x+1$ and $2 y = 4 x + 2$ $2y=4x+2$ ?
How do I use substitution to find the solution of the system of equations $y = \frac{1}{3} x + \frac{7}{3}$ $y=1/3x+7/3$ and...

Impact of this question

2021 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-24T09:59:52

Since $- 4 \neq 6$ $-4 !=6$ , then there is no solution

Explanation:

$3 x + y = 4$ $3x+y=4$ --- (1)
$- 6 x - 2 y = 12$ $-6x-2y=12$ --- (2)

From (1)
$3 x + y = 4$ $3x+y=4$
$y = 4 - 3 x$ $y=4-3x$ --- (3)

Sub (3) into (2)
$- 6 x - 2 y = 12$ $-6x-2y=12$
$- 3 x - y = 6$ $-3x-y=6$
$- 3 x - (4 - 3 x) = 6$ $-3x-(4-3x)=6$
$- 3 x - 4 + 3 x = 6$ $-3x-4+3x=6$
$- 4 = 6$ $-4=6$

Since $- 4 \neq 6$ $-4 !=6$ , then there is no solution

Science

Math

Humanities

... and beyond

How do you solve the system $3 x + y = 4$ $3x + y = 4$ , $- 6 x - 2 y = 12$ $-6x - 2y = 12$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the system 3x+y=43x + y = 4, −6x−2y=12-6x - 2y = 12?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve the system $3 x + y = 4$ $3x + y = 4$ , $- 6 x - 2 y = 12$ $-6x - 2y = 12$ ?