How do you solve the system $1 + t = 2 s$ $1 + t = 2s$ , $- 6 + 2 t = 4 + s$ $-6 + 2t = 4 + s$ , $2 + t = 1 + 2 s$ $2 + t = 1 + 2s$ ?

Question

1758 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-26T18:58:37

$s = 4, t = 7$ $s=4 , t=7$

$t = 2 s - 1$ $t=2s-1$ ,if we make $t$ $t$ the subject

Then substitute this into $- 6 + 2 t = 4 + s$ $-6+2t=4+s$

$\Rightarrow$ $=>$ $- 6 + 2 (2 s - 1) = 4 + s$ $-6+2(2s-1)=4+s$

Expand the bracket

$\Rightarrow$ $=>$ $- 6 + 4 s - 2 = 4 + s$ $-6+4s-2=4+s$

Collect like terms

$\Rightarrow$ $=>$ $- 8 + 4 s = 4 + s$ $-8+4s=4+s$

Add 8 to both sides

$\Rightarrow$ $=>$ $4 s = 12 + s$ $4s=12+s$

Subtract $s$ $s$ from both sides

$\Rightarrow$ $=>$ $3 s = 12$ $3s=12$

Divide both sides by 3

$\Rightarrow$ $=>$ $s = 4$ $s=4$

Substitute $s = 4$ $s=4$ into $1 + t = 2 s$ $1+t=2s$

$\Rightarrow$ $=>$ $1 + t = 2 \times 4$ $1+t=2xx4$

$\Rightarrow$ $=>$ $t = 7$ $t=7$

How do you solve the system 1+t=2s1 + t = 2s, −6+2t=4+s-6 + 2t = 4 + s, 2+t=1+2s2 + t = 1 + 2s?