How do you solve the quadratic #6y^2-13y+6=0# using any method?
2 Answers
Using the quadratic formula
Explanation:
The quadratic formula for the general quadratic (in
is
For the example:
giving
Explanation:
Use an AC method:
Look for a pair of factors of
The pair
Use this pair to split the middle term, then factor by grouping as follows:
#0 = 6y^2-13y+6#
#color(white)(0) = 6y^2-9y-4y+6#
#color(white)(0) = (6y^2-9y)-(4y-6)#
#color(white)(0) = 3y(2y-3)-2(2y-3)#
#color(white)(0) = (3y-2)(2y-3)#
Hence