How do you solve the quadratic 3+5/(2x)=1/x^2 using any method?

1 Answer
Sep 21, 2016

x =0.295 " or "x=-1.129

Explanation:

If you have an equation which has fractions, you can get rid of them by multiplying each term by the LCM of the denominators.

In the equation " "3+5/(2x)=1/x^2" the LCD is " color(blue)(2x^2)

color(white)(x)color(blue)(2x^2)xx3+color(blue)(cancel(2x^2)^x)xx5/(cancel(2x))=color(blue)(2cancelx^2)xx1/cancelx^2

color(white)(xxxxxxxxxxx)6x^2+5x=2" "larr no fractions!

6x^2 +5x -2 = 0" "rarr the options are: "find factors"
color(white)(xxxxxxxxxxxxxxxxx.xxxxxxxxx)"complete the square"
color(white)(xxxxxxxxxxxxxxxxx.xxxxxxxxx)"quadratic formula"

This quadratic expression does not factor, use the formula.

x = (-b +-sqrt(b^2 -4ac))/(2a)

x = (-5 +-sqrt(5^2 -4(6)(-2)))/(2(6))

x = (-5 +-sqrt(25 +48))/(12)

x = (-5 +sqrt(73))/(12)" or "x = (-5 +sqrt(73))/(12)

x =0.295 " or "x=-1.129