How do you solve the linear system using substitution $x = 17 - 4 y$ $x =17 - 4y$ , and $y = x - 2$ $y = x-2$ ?

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How do you solve the linear system using substitution $x = 17 - 4 y$ $x =17 - 4y$ , and $y = x - 2$ $y = x-2$ ?

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Answer 1 · 2015-05-07T00:03:23

Substitute $x = 17 - 4 y$ $x=17-4y$ into the second equation so you get:
$y = 17 - 4 y - 2$ $y=17-4y-2$
$5 y = 15$ $5y=15$
$y = 3$ $y=3$
Substitute this values of $y$ $y$ back into the first equation to get:
$x = 17 - 4 \cdot 3 = 17 - 12 = 5$ $x=17-4*3=17-12=5$
So your solution is:
$x = 5$ $x=5$
$y = 3$ $y=3$

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How do you solve the linear system using substitution $x = 17 - 4 y$ $x =17 - 4y$ , and $y = x - 2$ $y = x-2$ ?

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How do you solve the linear system using substitution x=17−4yx =17 - 4y, and y=x−2y = x-2?

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How do you solve the linear system using substitution $x = 17 - 4 y$ $x =17 - 4y$ , and $y = x - 2$ $y = x-2$ ?