How do you solve the equations #22=7-3a#?

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Answer 1 · 2018-04-06T10:19:49

#color(magenta)(a=-5#

#22=7-3a#

Adding #-7# to both sides:

#-3a+cancel7-cancel7=22-7#

#-3a=15#

#(-cancel(3)a)/(cancel3)=15/3#

#-a=5#

#color(magenta)(a=-5#

~Hope this helps! :)