How do you solve the equation $x^2+a=4$ ?

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Answer 1 · 2017-07-26T07:25:52

Arrange your equation

Arrange your equation

$x^2 = 4-a$

$x = sqrt(4-a)$

a must be less than or equal to 4.

$x=sqrt(4-a)$

If a is 1, for instance, you can get:

$x=sqrt3$

How do you solve the equation x^2+a=4x^2+a=4?