How do you solve the equation $\frac{{(x - 2)}^{2}}{4} + \frac{3}{2} = \frac{5}{3}$ $(x-2)^2/4+3/2=5/3$ ?

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Answer 1 · 2017-08-20T11:37:46

$2 \pm \frac{2}{\sqrt{6}} .$ $2pm2/sqrt6.$

We have, $\frac{{(x - 2)}^{2}}{4} + \frac{3}{2} = \frac{5}{3},$ $(x-2)^2/4+3/2=5/3,$

$:. {(x-2)/2}^2=5/3-3/2={(5*2-3*3)/(3*2)}=1/6,$

$:. (x-2)/2=pmsqrt(1/6),$

$:. x-2=pm2/sqrt6,$

$:. x=2pm2/sqrt6.$

How do you solve the equation (x-2)^2/4+3/2=5/3(x−2)24+32=53(x-2)^2/4+3/2=5/3?