How do you solve the equation $x^{2} + 169 = 0$ $x^2+169=0$ ?

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Answer 1 · 2017-04-16T00:06:05

NO REAL SOLUTIONS but rather complex solutions:

$x = - 13 i, 13 i$ $x = -13i, 13i$

Isolate the $x^{2}$ $x^2$ by subtracting 169 from both sides...

$x^2+cancel(169-169)=0-169 -> x^2 = -169$

Now take the square root of both sides to the $x$

$sqrt(x^2)= sqrt(-169) -> x= +- sqrt(-169)$

Note: there are NO REAL SOLUTIONS! but rather two complex solutions denoted by the symbol $i$

So $x = -13i, 13i$

How do you solve the equation x^2+169=0x2+169=0x^2+169=0?