How do you solve the equation $sqrtt+sqrt(1+t)-4=0$ to find the zeros of the given function?

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Answer 1 · 2016-12-17T09:58:36

$t = (15/8)^2$

First we establish the feasible solutions. They must obey:

From $sqrt(t)->t ge 0$ and from $sqrt(1+t)->1+t ge 0$ so
$t ge 0$

Now grouping

$sqrt(t+1) = 4 - sqrt(t)$

and squaring

$t+1=16-8sqrt(t)+t$ simplifying

$8sqrt(t)=15$ so

$t = (15/8)^2 > 0$

so the solution is feasible

How do you solve the equation sqrtt+sqrt(1+t)-4=0sqrtt+sqrt(1+t)-4=0 to find the zeros of the given function?