How do you solve the equation and express in simplest radical form for $(4x+3)^2=7$ ?

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Answer 1 · 2018-06-20T08:14:31

$color(green)(x = (-3 +- sqrt7)/4$

$(4x + 3)^2 = 7$

$(4x + 3)^2 = (sqrt7)^2$

$4x + 3 = +- sqrt7$

$4x = -3 +- sqrt7$

$color(green)(x = (-3 +- sqrt7)/4$

How do you solve the equation and express in simplest radical form for (4x+3)^2=7(4x+3)^2=7?