How do you solve the equation 5(x-4)^2=1255(x−4)2=125?
1 Answer
May 5, 2017
Explanation:
color(blue)"Isolate " (x-4)^2" by dividing both sides by 5"Isolate (x−4)2 by dividing both sides by 5
(cancel(5)(x-4)^2)/cancel(5)=125/5
rArr(x-4)^2=25
color(blue)"take the square root of both sides"
sqrt((x-4)^2)=color(red)(+-)sqrt25larr" note plus or minus"
rArrx-4=+-5
"add 4 to both sides"
xcancel(-4)cancel(-4)=+-5+4
rArrx=4+-5
rArrx=4+5=9" or " x=4-5=-1
color(blue)"As a check" Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
x=-1to5(-1-4)^2=5xx5^2=125
x=9to5(9-4)^2=5xx5^2=125
rArrx=-1" or " x=9" are the solutions"
