How do you solve the equation #3x^2-150=-282#?

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Answer 1 · 2017-06-02T21:20:30

No real solution

Complex solutions: #x = +- 2sqrt(11) i#

Given: #3x^2 - 150 = -282#

Start by adding #282# to both sides of the equation: #3x^2 - 150 + 282 = 0#

#3x^2 + 132 = 0#

Factor the greatest common factor (GCF) of #3#:

#3(x^2 +44) = 0#

If you divide both sides by #3# you get:

#x^2 + 44 = 0#

#x^2 = -44#

When you square root both sides you will get a negative value which yields a complex solution since #sqrt(-1) = i#:

#x = +-sqrt(-44) = +- 2 sqrt(-11) = +- 2sqrt(11) i#

No real solution.