How do you solve the equation $3x^2-150=-282$ ?

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Answer 1 · 2017-06-02T21:20:30

No real solution

Complex solutions: $x = +- 2sqrt(11) i$

Given: $3x^2 - 150 = -282$

Start by adding $282$ to both sides of the equation: $3x^2 - 150 + 282 = 0$

$3x^2 + 132 = 0$

Factor the greatest common factor (GCF) of $3$ :

$3(x^2 +44) = 0$

If you divide both sides by $3$ you get:

$x^2 + 44 = 0$

$x^2 = -44$

When you square root both sides you will get a negative value which yields a complex solution since $sqrt(-1) = i$ :

$x = +-sqrt(-44) = +- 2 sqrt(-11) = +- 2sqrt(11) i$

No real solution.

How do you solve the equation 3x^2-150=-2823x^2-150=-282?