How do you solve the equation $2 x^{2} + 5 = 5 x^{2} - 37$ $2x^2+5=5x^2-37$ ?

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Answer 1 · 2017-04-29T09:21:44

$x = \pm \sqrt{14}$ $x=pmsqrt14$

$2 x^{2} + 5 = 5 x^{2} - 37$ $2x^2+5=5x^2-37$

$5 + 37 = 5 x^{2} - 2 x^{2}$ $5+37=5x^2-2x^2$

$42 = 3 x^{2}$ $42=3x^2$

$\frac{42}{3} = x^{2}$ $42/3=x^2$

$x^{2} = 14$ $x^2=14$

$x = \pm \sqrt{14}$ $x=pmsqrt14$

How do you solve the equation 2x^2+5=5x^2-372x2+5=5x2−372x^2+5=5x^2-37?