How do you solve the equation $2x^2+338=0$ ?

Question

2919 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-08T22:39:53

$x=+-13i$

First, we need to isolate $x$ :

$2x^2+338=0$

subtract $338$ on both sides

$2x^2=-338$

divide by $2$

$x^2=-169$

take the square root of both sides

$+-cancel(sqrt(x^cancel(2))$ $=+-sqrt(-169)$

$x=+-13i$

The $i$ comes from $sqrt(-1)$

How do you solve the equation 2x^2+338=02x^2+338=0?