How do you solve the equation $2 x^{2} + 338 = 0$ $2x^2+338=0$ ?

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Answer 1 · 2017-05-08T22:39:53

$x = \pm 13 i$ $x=+-13i$

First, we need to isolate $x$ $x$ :

$2 x^{2} + 338 = 0$ $2x^2+338=0$

subtract $338$ $338$ on both sides

$2 x^{2} = - 338$ $2x^2=-338$

divide by $2$ $2$

$x^{2} = - 169$ $x^2=-169$

take the square root of both sides

$+-cancel(sqrt(x^cancel(2))$ $=+-sqrt(-169)$

$x=+-13i$

The $i$ comes from $sqrt(-1)$

How do you solve the equation 2x^2+338=02x2+338=02x^2+338=0?