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How do you solve $tanxsin^2x=tanx$ ?

1 Answer

May 1, 2015

$f(x) = tan x. sin^2 x - tan x = 0$

$= tan x (sin^2 x - 1) 0$
Next, solve the 3 basic trig equations: tan x = 0; sin x = 1;
and sin x = -1.

$tan x = 0 --> x = 0 and x = Pi$

$sin x = 1 --> x = Pi/2$

$sin x = -1 --> x = (3Pi)/2$

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