How do you solve #tanxcscx-2tanx=0#?

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How do you solve #tanxcscx-2tanx=0#?

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Answer 1 · 2016-08-24T04:39:43

#0, pi/3, pi, (5pi)/3, 2pi#

Explanation:

Trig table of special arcs, and unit circle -->
tan x.csc x - 2tan x = 0
tan x(csc x - 2) = 0
One of the 2 factors should be 0 -->
a. tan x = 0 -->
arc x = 0, and #x = pi, and x = 2pi#
b. #csc x = 1/(cos x) = 2#
#cos x = 1/2#-->
Arc #x = +- pi/3#
Note: arc #-pi/3# --> arc #(5pi)/3# (co-terminal)
Answers for #(0, 2pi)#:
#0, pi/3, pi, (5pi)/3, and 2pi#

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How do you solve #tanxcscx-2tanx=0#?

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