How do you solve #tan(x)(tanx+1)=0#?

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Answer 1 · 2018-03-29T05:44:10

#x=0,(3pi)/4, pi,(7pi)/4,,2pi, (11pi)/4, 3pi,(15pi)/4,....#

#tanx(tanx+1)=0#

#tanx=0#

#x=0,pi,2pi,3pi,....#

#tanx+1=0#

#tanx=-1#

#x=pi-pi/4, 2pi-pi/4, 3pi-pi/4,4pi-pi/4,...#

#x=(3pi)/4, (7pi)/4, (11pi)/4, (15pi)/4,....#

Combining and arranging in the increasing order

#x=0,(3pi)/4, pi,(7pi)/4,,2pi, (11pi)/4, 3pi,(15pi)/4,....#