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How do you solve $tan(x)=cot(x)$ ?

1 Answer

Apr 16, 2015

First of all the conditions:

since there is the $y=tanx$ function, $x!=pi/2+kpi$

since there is the $y=cotx$ function, $x!=kpi$ .

So, together: $x!=kpi/2$ .

Than, remembering that $cotx=1/tanx$ ,

$tanx=1/tanxrArrtan^2x=1rArrtanx=+-1rArr$

$x=+-pi/4+kpi$ both acceptable.

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