How do you solve #Tan(55)= (c+4)/c#?

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Answer 1 · 2018-04-23T03:00:49

The answer is #c=4/(tan55-1)#.

To solve for #c#, get rid of the denominator, then move all the parts containing #c# to one side, then factor out #c#:

#tan55=(c+4)/c#

#tan55color(blue)(*c)=(c+4)/(c)color(blue)(*c)#

#tan55color(blue)(*c)=(c+4)/color(red)cancelcolor(black)(c)color(blue)(*color(red)cancelcolor(blue)c)#

#ctan55=c+4#

#ctan55-c=4#

#c(tan55-1)=4#

#color(blue)(color(black)(c(tan55-1))/(tan55-1))=color(blue)(color(black)4/(tan55-1))#

#color(blue)(color(black)(c color(red)cancelcolor(black)((tan55-1)))/color(red)cancelcolor(blue)(tan55-1))=color(blue)(color(black)4/(tan55-1))#

#c=color(blue)(color(black)4/(tan55-1))#

#color(white)c~~9.3425636...#

That's the solution. Hope this helped!