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How do you solve ${tan}^{2} x = cos x {tan}^{2} x$ $tan^2x=cosxtan^2x$ ?

1 Answer

Nov 15, 2016

${tan}^{2} x - cos x {tan}^{2} x = 0$ $tan^2x - cosxtan^2x = 0$

${tan}^{2} x (1 - cos x) = 0$ $tan^2x(1 - cosx) = 0$

${tan}^{2} x = 0 and cos x = 1$ $tan^2x= 0 and cosx = 1$

$x = 0 + π n, 180 + π n, 180 + 2 π n$ $x = 0 + pin, 180 + pin, 180 + 2pin$

Hopefully this helps!

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