How do you solve ${tan}^{2} x = 3$ $tan^2x=3$ ?

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Answer 1 · 2018-05-07T02:31:33

$x = n π \pm \frac{π}{3}, \frac{π}{3} 0 \in n$ $color(crimson)(x = npi +- pi/3, pi/3 0 in n$

${tan}^{2} x = 3$ $tan ^2 x = 3$

Taking square root on both sides,

$tan x = \pm \sqrt{3}$ $tan x = +- sqrt3$

$x = n π + \frac{π}{3}, n π - \frac{π}{3}, \frac{π}{3} 0 \in n$ $color(crimson)(x = npi + pi/3, npi-pi/3, pi/3 0 in n$

How do you solve tan^2x=3tan2x=3tan^2x=3?