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How do you solve #tan^2 x=tan x#?

1 Answer

Jan 28, 2016

#x = kpi# or #x = pi/4 + kpi# where #k in ZZ#

Explanation:

#tan^2x = tanx#

#=> tan^2x - tanx = 0#

#=> tanx(tanx - 1) = 0#

#=> tanx = 0# or #tanx = 1#

#=> sinx/cosx = 0# or #sinx/cosx = 1#

#=> sinx = 0# or #sinx = cosx#

#:. x = kpi# or #x = pi/4 + kpi# where #k in ZZ#

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