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How do you solve #tan^2 (x) = 1/3# from #[0,2pi]#?

1 Answer

Jul 20, 2015

Solve #tan^2 x = 1/3 # # (0, 2pi)#

Explanation:

#tan^2 x = 1/3.# --> #tan x = +- (sqrt3)/3#. Trig table gives -->

#x = pi/6 + kpi # and #x = (5pi)/6+ kpi#

Within the interval (0, 2pi), there are 4 answers:

#(pi)/6; and (pi/6 + pi) = (7pi)/6, (5pi)/6; and ((5pi)/6 + pi) = (11pi)/6#

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