How do you solve $\sqrt{x} + 12 = x$ $sqrtx+12=x$ ?

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How do you solve $\sqrt{x} + 12 = x$ $sqrtx+12=x$ ?

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Answer 1 · 2015-04-18T18:55:44

Take $12$ $12$ to the right and then square both sides to get:
$x = {(x - 12)}^{2}$ $x=(x-12)^2$
$x = x^{2} - 24 x + 144$ $x=x^2-24x+144$
$x^{2} - 25 x + 144 = 0$ $x^2-25x+144=0$
Solve for $x$ $x$ and then check the results (you´ll get 2 of which only one acceptable) by substituting back into your original equation.

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How do you solve $\sqrt{x} + 12 = x$ $sqrtx+12=x$ ?

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