How do you solve $sqrt(x+5)=1-x$ ?

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Answer 1 · 2016-05-14T00:25:31

$sqrt(x + 5) = 1 - x$

$(sqrt(x + 5))^2 = (1 - x)^2$

$x + 5 = 1 - 2x + x^2$

$0 = x^2 - 3x - 4$

$0 = (x - 4)(x + 1)$

$x = 4 and -1$

However, after checking in the original equation we find that only $x= -1$ works.

The solution set is ${-1}$ .

Hopefully this helps!

How do you solve sqrt(x+5)=1-x sqrt(x+5)=1-x ?