How do you solve #sqrt(x + 4) = -3#?

1 Answer

There is no solution

Explanation:

We're dealing with a square root and equating it to a negative number - which is something we can't do.

For example, if #x=-4#, then the square root is #sqrt((-4)+4)=sqrt0=0#

If, however, we change the value of #x# to #x=-5#, then

#sqrt((-5)+4)=sqrt(-1)=i#

and so there's no way to get a negative value from a square root.