How do you solve $sqrt(x+3)= x-3$ ?

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Answer 1 · 2016-05-23T10:36:34

$x=+1" and "x=+6$

Square both sides

$x+3=(x-3)^2" "->" "x+3=x^2-6x+9$

Subtract $x$ from both sides

$3=x^2-7x+9$

Subtract 3 from both sides

$0=x^2-7x+6$

Notice that $(-1)xx(-6) = +6" and "-1-6=-7$

Factorising

$=>0=(x-1)(x-6)$

$x=+1" and "x=+6$

How do you solve sqrt(x+3)= x-3sqrt(x+3)= x-3?