How do you solve $sqrt(x/10) = sqrt(3x-58)$ ?

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Answer 1 · 2015-08-06T06:08:05

$color(blue)(x=20$

$sqrt(x/10) = sqrt(3x-58)$

Squaring both sides eliminates the square root.

$(sqrt(x/10) )^2= (sqrt(3x-58))^2$

We get:

$x/10 = 3x -58$

$x= (3x -58)* 10$

$x= 30x -580$

$580 = 30x -x$

$29x= 580$

$color(blue)(x=20$

How do you solve sqrt(x/10) = sqrt(3x-58)sqrt(x/10) = sqrt(3x-58)?