How do you solve #sqrt(x/10) = sqrt(3x-58)#?

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Answer 1 · 2015-08-06T06:08:05

#color(blue)(x=20#

#sqrt(x/10) = sqrt(3x-58)#

Squaring both sides eliminates the square root.

#(sqrt(x/10) )^2= (sqrt(3x-58))^2#

We get:

#x/10 = 3x -58#

#x= (3x -58)* 10#

#x= 30x -580#

#580 = 30x -x#

#29x= 580#

#color(blue)(x=20#