How do you solve $sqrt(x+1)-7=0$ ?

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Answer 1 · 2016-04-10T13:37:33

$x=48$

Our aim is to find the value of $x$

$color(blue)(sqrt(x+1)-7=0$

Add $7$ both sides

$rarrsqrt(x+1)cancel(-7+7)=0+7$

$rarrsqrt(x+1)=7$

Square both sides to get rid of the radical sign ( $sqrt$ )

$rarr(sqrt(x+1))=7^2$

$rarrx+1=49$

Subtract $1$ both sides

$rarrxcancel(+1-1)=49-1$

$color(green)(rArrx=48$

How do you solve sqrt(x+1)-7=0sqrt(x+1)-7=0?